For this assignment, you submit answers by question parts. The number of submiss

Question

For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change Assignment Scoring Your last submission is used for your score -10 points UCF ColPhysEML1 7 PRE 001 A charged particle moving through a magnetic field at right angles to the field with a speed of 25.7 m/s experiences a magnetic force of 2.98 x 10 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 4.34 m/'s at an angle of 34.2 relative to the magnetic field. N Tutorial Additional Materials Magnetic Field of a Permanent Magnet My As shown in the figure, two frictionless conducting rails (#1 and #2) are attached to a 20.0ncline such that the inside edges are 80.0 cm apart. A copper bar with a mass of 0.317 kg slides (without friction) at a constant speed down the conducting rails Sliding bar If there is a vertical magnetic field of 0.0346 T in magnitude in the region of the incline, determine the magnitude of the current that flows through the sliding copper bar What is the direction of the current in the sliding bar? from rail #1 to rail #2 from rail #2 to rail #1 Tutorial Additional Materials Magnetic Field of a Permanent Magnet

Explanation / Answer

1.

q = charge on the particle

v1 = speed for the particle moving at right angle = 25.7 m/s

F = magnetic force experienced = 2.98 x 10-4 N

B = magnetic field = ?

Using the equation

F = q v1 B Sin90

2.98 x 10-4 = q B (25.7)

qB = 0.116 x 10-4 eq-1

when the particle moves at angle 34.2 deg

q = charge on the particle

v1 = speed for the particle moving at right angle = 25.7 m/s

F = magnetic force experienced = 2.98 x 10-4 N

B = magnetic field = ?

Using the equation

F' = q v2 B Sin34.2

F' = (0.116 x 10-4) (4.34) Sin34.2

F' = 2.83 x 10-5 N

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