Pushing a Block A constant force acts for a time V. on a block that is initially

Question

Pushing a Block A constant force acts for a time V. on a block that is initially at rest on a frictionless surface, resulting in a final velocity 1) Suppose the experiment is repeated on a block with twice the mass using a force that's half as big. For how long would the force have to act to result in the same final velocity? Four times as long. Twice as long. The same length. Half as long. one quarter as long. Submit Survey Question) 2) Briefly explain your answer to the previous question. Submit Copyright © 2018 Freeman Worth Publishers . a division of Macmillan Learning About I Tech Support Find Your Local Sales Rep I Terms Of Use I Privacy Policy MacBook Pro Q search or enter website name

Explanation / Answer

acceleration = F/m

v = u + at

v = F/m*t

new acceleration = F/2m

v = 0 + F/2m t1

Ft1 / 2m = Ft / m

t1 = 2t

so it will take twice the time

so second option is correct

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