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44 points SerCP1 = 0.43e Starting from rest, a 5.60-kg block slides 1.90 m down

ID: 1582813 • Letter: 4

Question

44 points SerCP1 = 0.43e Starting from rest, a 5.60-kg block slides 1.90 m down a rough 30.0° incline. The coefficient of kinetic friction between the block and the incline is a) Determine the work done by the force of gravity (b) Determine the work done by the friction force between block and incline. (c) Determine the work done by the normal force. (d) Qualitatively, how would the answers change if a shorter ramp at a steeper angle were used to span the same vertical height? 1 n This answer has not been graded yet

Explanation / Answer

a)

Work Done by Force of gravity

W=Mgsin(o)*d

W=5.6*9.81*sin30*1.9

W=52.2 J

b)

Work done by frictional force

W=-umgCos(o)*d

W=-0.436*5.6*9.81*Cos30*1.9

W=-39.4 J

c)

Work done by normal foce

W=0 J (Since there is no motion in y-direction)

d)

Work done by Frictional force decreases ,and Work done by gravity and normal force does not change

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