show work please and thank you relationship for voltage and eurrent for the circ
ID: 1582834 • Letter: S
Question
show work please and thank you
relationship for voltage and eurrent for the circuit v is the battery voltage, v, is the voltage drop across bulb 1 . V2 is the voltage drop across 6) Two light bulbs are connected to a battery shown in the cireuts below, chose the com bulb 2 Cireuit Circuit # 1 B) D) E) 7) In the circuit shown in the figure, all the light bulbs are identical. Which of the following is the correct ranking of the brightness of the bulbs? A) B and C have equal brightness, and A is the dimmest. B) A and B have equal brightness, and C is the dimmest. C) A is brightest, C is dimmest, and B is in between. D) A is the brightest, and B and C have equal brightness but less than A. E) All three bulbs have the same brightness A. 8) Two Light bulbs are wire in parallel with a power source, what is the equivalent resistance of the circuit? A) 15 B) 10 C)25 D) 12 E) 50 R1 R2 R1-30 R2-20 9) In the circuit diagram below, what is the voltage across resistor RA? A) 200 V B) 120 V C) 140 V D) 240 V E) 100 v RI R1=75 R4 R3-100 R4 = 200 2 of 7Explanation / Answer
(6) In a series circuit,current flowing through all series elements are Equal
So Iin = Iout = i1=i2
and applied voltage V = V1+V2 = sum of voltage drop across bulbs
Answer is (E)
(7)Segment with 2 bulbs has higher resisitance than single bulb, hence more current flows through single bulb,hence power dissipated ( VI ) is greater in single bulb,hence it glows brighter. The 2 bulbs in other segment are in series and hence they both are equally bright.
So answer is D
(8) R(Eq) = R1 x R2 / (R1+R2) = 30 X 20 /(30+20) = 12 Ohms
(9) Equivalent resistance for R2 and R3 which are parallel = R2 X R3 /( R2+R3) = 200 X 100 /( 200+100) = 200/3 ohms
Total circuit resistance = R1 + R4 + 200/3 = 75 +200 + 200/3 =75+200+66.7 = 341.7 ohms
V = 240 V
I =240 V / 341.7 ohms
Voltage across R4 = (240/341.7) X 200 = 140.5 Volts
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