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://edugen.wileyplus.com/edugen/student/mainfr.uni nt BACK Chapter 24, Problem 41

ID: 1582980 • Letter: #

Question

://edugen.wileyplus.com/edugen/student/mainfr.uni nt BACK Chapter 24, Problem 41 The average intensity of light emerging from a polarizing sheet is 0.740 W/m2, and that of the horizontally polarized light incident on the sheet is 0.850 W/m2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal. Incident beam Transmitted beam Number Units the tolerance is +/-296 SAVE FOR LATER Question Attempts: Unlimited Version 4.24 51 Ies. All Rights Reserved. A Division of John Wiley &.5ons Inc 5

Explanation / Answer


use malus law as

I = Io cos^2 theta

Cos^2 theta = I/Io

Cos^2 theta = 0.740/0.850

Cos^2 theta = 0.8705

cos theta = 0.933

theta = 21.08 deg

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