Constanta Part A An electron at point A in the figure (Figure 1) has a speed of

Question

Constanta Part A An electron at point A in the figure (Figure 1) has a speed of 1 46x 106 m/s Find the direction of the magnetic fleld that will cause the electron to follow the semicircular path from A to E Please Choose Submit Request Answer Part B Find the magnitude of the magnetic field that will cause the electron to follow tha semicircular path from A to B Submit Part C ind the time required for the alactron to mova from A n B Submt Figure of 1 Part D Find the direction of the magnelic field, that would be needed if the particle were a protern instead af an electrun? Plaase Chonse Submt

Explanation / Answer

Solution) (A)the direction is into the page

(B) we have r=mv/Bq

B=mv/tq

B=9.1×10^(-31)×1.46×10^(6)/(10×10^(-2)×1.6×10^(-19))

B=8.303×10^(-4)T

(C) time t=(pi×r)/V

t=3.14×5×10^(-2)/(1.46×10^(6))

t=10.75×10^(-8) s

(D) direction is out of the page

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