Questions 17-18 refer to the circuit below containing a battery, a capacitor, a
ID: 1583234 • Letter: Q
Question
Questions 17-18 refer to the circuit below containing a battery, a capacitor, a bulb and a switch. The switch is initially open as shown in the diagram, and the capacitor is uncharged. Which statement correctly describes what happens to the bulb when the switch is closed?
1.The bulb is dim and remains dim.
2.At first the bulb is dim and it gets brighter and brighter until its brightness levels off.
3.The bulb is bright and remains bright.
4.At first the bulb is bright and it gets dimmer and dimmer until it goes off.
Which correctly describes what happens after the switch has remained closed for a long time?
1.The bulb continues to shine brightly.
2.The bulb no longer shines.
3.The potential difference across the capacitor is steady.
4.The current in the circuit is steady and large.
5.None of these is correct.
D Question 17 1 pts Questions 17-18 refer to the circuit below containing a battery, a capacitor, a bulb and a switch. The switch is initially open as shown in the diagram, and the capacitor is uncharged. Which statement correctly describes what happens to the bulb when the switch is closed? The bulb is dim and remains dim. At first the bulb is dim and it gets brighter and brighter until its brightness levels off. The bulb is bright and remains bright. At first the bulb is bright and it gets dimmer and dimmer until it goes off. DQuestion 18 1 pts Which correctly describes what happens after the switch has remained closed for a long time? The bulb continues to shine brightly. The bulb no longer shines. The potential difference across the capacitor is steady and much smaller than the emf of the battery The current in the circuit is steady and large. None of these is correct.Explanation / Answer
Answer 17,option 4,initially capacitor is uncharged,untill it fully charge current passes through it,when capicstor fully charged ,no current passes through capictor,circuit break and bulb off.
Answer 18, bulb no longer shine because when capictor fully charged ,no current passess through capicator,circuit breaks and bulb no longer shine.
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