A velcro-covered beanbag is fired into a empty wooden crate that is sitting on a

Question

A velcro-covered beanbag is fired into a empty wooden crate that is sitting on a concrete floor and is open on one side. The beanbag launcher is set up such that the beanbag is moving purely horizontally when it strikes and sticks to the inside, velcro-lined wall of the crate. As a result of this impact, the crate slides backwards 0.843 meters along the concrete ( coefficient of kinetic friction of k = 0 . 5 0 k =0.50). The beanbag has a mass of 0.271 kg and the empty crate has a mass of 3.3 kg. Calculate the velocity of the beanbag. You may neglect the effect of air resistance.

Explanation / Answer

According to the given problem,

Given, uk = 0.5

From probelm, the deaccelration due to friction , a = ukg

a = 4.9 m/s2

S = 0.843 m

Using kinamatic equation of motion,

the speed of combination after the impact , v= 2aS

v = 2.87 m/s

let the initial speed of the beanbag be u

Using conservation of momentum for the collison

0.271 * u = ( 0.271 + 3.3) * v

0.271 * u = ( 0.271 + 3.3) * 2.87

u = 37.87 m/s.

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