Question 13 of 15 Incorrect Map Openstax College Physics presented by Sapling Le

Question

Question 13 of 15 Incorrect Map Openstax College Physics presented by Sapling Learning A heart defibrillator being used on a patient has an RC time constant of 11.0 ms due to the resistance of the patient and the capacitance of the defibrillator. If the defibrillator has an 7.25 uF capacitance, what is the resistance of the path through the patient? Number 1.52x 103 If the initial voltage is 12.0 kV, how long does it take to decline to 427 V? Number 0114 There is additional feedback available! View this feedback by clicking on the bottom divider bar. Click on the divider Incorrect. bar again to hide the additional feedback. Close O Previous Give Up & View Solution # Try AgainNext Exit Explanation

Explanation / Answer

Here ,

T = 11 ms

C = 7.25 uF

let the resistance of the path is R

T = R * C

0.011 = R * 7.25 *10^-6

solving for R

R = 1517 Ohm

the resistance is 1517 Ohm

---------------------------------

let the time taken is t

427 = 12000 * (e^(-t/11))

solving for t

t = 36.7 ms

the time taken is 36.7 ms

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