1-4 please 1. Consider an object with a mass of 12.5 kg moving at a constant spe

Question

1-4 please

1. Consider an object with a mass of 12.5 kg moving at a constant speed in a circular path with a radius of <2.30+B> m. The object makes one full revolution in <7.60 + A> seconds. Calculate the centripetal acceleration of the object. Give your answer in m/s2 and with 3 significant figures.   A = 8 and B = 6.

2. A car with mass (425 + C) kg attempts to make a turn with a radius of (22.8 + A) m at a speed of (12.5 + B) m/s on a horizontal surface. What is the minimum value for the static coefficient of friction between the tires and the roadway necessary for the car to make the turn without sliding? Give your answer with 3 significant figures.  A = 8, B = 6, and C = 20

3. A bicyclist with mass (45.0+C) kg wants to make a turn with a radius of (18.5 + B) m on a horizontal surface. If she is riding at a speed of (5.45 + A) m/s, at what angle from the vertical will she need to lean to make the desired turn? Give your answer in degrees and with 3 significant figures. A = 8, B = 6, and C = 20

4. A student with mass (38.0+C) kg rides on a roller coaster with a vertical loop. At the top of the loop the track has a radius of (14.7 + B) m and the roller coaster moves at speed of (16.9 + A) m/s at the top. Determine the normal force from the seat on the student at the top of the loop. Give your answer in newtons (N) and with 3 significant figures. A = 8, B = 6, and C = 20

Explanation / Answer

Given,

m = 12.5 kg ;

r = 2.3 + B = 2.3 + 6 = 8.3 m

t = 7.6 + A = 7.6 + 8 = 15.6 s

frequency = f = 15.6 rev/s

w = 98.02 rad/s

We know that the centripital acceleration is given by:

ac = v^2/r

v = r w = 8.3 x 98.2 = 815.06 m/s

ac = (815.06)^2/8.3 = 80039 m/s^2

Hence, ac = 8.004 x 10^4 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.