(25 points) A ball is rolling at 1.00 m/s on a flat table. It rolls off the edge
ID: 1584492 • Letter: #
Question
(25 points) A ball is rolling at 1.00 m/s on a flat table. It rolls off the edge of the tabletop, which is 80 m above the ground. (a) What is the ball's initial velocity (at the instant it rolls off the table) parallel to the ground Perpendicular to the ground? (b) What is the ball's acceleration parallel to the ground? Perpendicular to the ground? (c) How long will it take for the ball to reach the ground after it rolls off the table? (d) How far from the foot of the table will the ball hit the ground? (Assume the foot of the t is on the ground is right under the point where the ball leaves the table.)Explanation / Answer
(A) parallel to ground,
v0x = 1 m/s
perpendicular to the ground,
v0y = 0
(B) parallel, a_x = 0
perpendicular, a_y = - 9.8 m/s^2
(C) in vertical,
yf - yi = v0y t + ay t^2 / 2
0 - 0.80 = 0 - 9.8 t^2 /2
t = 0.404 sec
(D) parallel to ground,
x = (v0x) t = 1 x 0.404
x = 0.404 m
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