OmeworkR Section 12.3 × Physics 4A-sJCC SPRING2018 MasteringPhysks: HW chapter 3

Question

OmeworkR Section 12.3 × Physics 4A-sJCC SPRING2018 MasteringPhysks: HW chapter 3-Mocilla Firef tProblemID 92593410 HW chapter 3 Problem 3.51 Part A A toy rocket is launched with an initial velocity of 10 0 m/s in the horizortal direction from the rool of a 3t 0 m tall buildng The rocket's engine produces a honizentai acceleratien of (i so What honental distance does the rocket travel before reaching the ground? ha 1.60 m/s')t, n the same drection as the initial Value Units Subm Revest Answer Provide Feedback 3 56 3.48 seno

Explanation / Answer

For travelling 38m downwards s=38, without any initial velocity u=0, time taken can be found by s=ut+0.5gt^2

So, 38= 0.5*9.8*t^2

So, t=2.78s

Now, distance covered along horizontal=s, with initial velocity u= 10 m/s, a= 1.6t m/s^2, t=2.78s can be found by

S= integral(udt) from t=0 to t=2.78 + integral (atdt) from t=0 to t=2.78

So, horizontal distance the rocket travels before reaching the ground is 10*2.78+ 1.6*2.78^3 / 3 = 27.8+ 11.46 = 39.26 m

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