Problem 25.71 Part A Unpolarized light passes through a vertical polarizing filt

Question

Problem 25.71 Part A Unpolarized light passes through a vertical polarizing filter, emerging with an intensity Io. The light then passes through a horizontal filter, which blocks all of the light; the intensity transmitted through the pair of filters is zero. Suppose a third polarizer with axis 45° from vertical is inserted between the first two. What is the transmitted intensity now? Express your answer in terms of lo SubmitPre Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Provide Feedback

Explanation / Answer

Using I = Io*cos^2(theta)

given that theta = 45 deg

after passing through second filter ,the intensity is I = Io^2*cos^2(45) = Io/2

from the 3rd filter ,the intensity is

I1 = I*cos^2(theta)

I1 = I*cos^2(45) = (Io/2)*(1/2) = Io/4

I1 = 0.25*Io

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