(11%) Problem 7: A child of mass m = 22 kg slides down a slide of height h = 2.7
ID: 1585235 • Letter: #
Question
(11%) Problem 7: A child of mass m = 22 kg slides down a slide of height h = 2.7 m without friction. Let gravitational potential energy be zero at ground level. Randomized Variables m 22 kg h= 2.7 m > 33% Part (a) Write an expression for the child's total mechanical energy, E, at the top of the slide Grade Summary Deductions Potential 0% 100% 7 8 9 Submissions ts remaining:5 (090 per attempt) detailed view Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 3 Feedback: 0% deduction per feedback. 33% Part b) Calculate the change in the child's potential energy, Un Joules from the top to the bottom of the slide at ground level (ie AU-Uground - Utop 33% Part (c) What is the child's final speed, yin ms?Explanation / Answer
see .as in the above question the answer is seeking total mechanical
energy.
so at the top of the slide.the child is still so kinetic energy=0.
but the child is at the height of 2.7m from ground.so
potential energy will become=m*g*h.=22*9.8*2.7=582.12J
so net mechanical energy =kinetic energy+potential energy
=0+582.12=582.12J.
hope you like my explanation.youay rate if you like
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