essicn masteringphysics.com/myct/ma steringe/assignment/6170450 Facebok TEC Univ

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essicn masteringphysics.com/myct/ma steringe/assignment/6170450 Facebok TEC Univestes a Kar yer-OSM i Tureng. Turkge Ing D ounction har input E Masten g physics [F Mashenngphysics HV.2 . Google Chrome “ Guveni I https//session masteringehysicscommyditem View?assignmentProblemID. 92780953 Problem 2.64 Constants Eeiodc Table -Part A A ball is dropped trom the top of a 510 m high cit At the same sme, a carefuly aimed stone is thrown straight up from the bottorn of the cit with a speed of 0 m/s The stone and ball collide part way up Hovw far above the base of the citt does this happen? Submit RequestAnswer Provide Feedback

Explanation / Answer

Using formula

Distance = V initial * time + ½ * a * t^2

Ball
V initial = 0
D ball = ½ * 9.8 * t^2

Stone
Vi = 22 m/s
D stone = 22 * t – ½ * 9.8 * t^2

D ball + D stone = 51 m
½ * 9.8 * t^2 + 22 * t – ½ * 9.8 * t^2 = 51

22 t = 51
t = 2.3182 seconds

D ball = ½ * 9.8 * 2.3182^2 = 26.33 m
D stone = 22* 2.3182 – ½ * 9.8 * t^2 = 24.67m

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