A 0.17-kg cue ball rests on the pool table. It\'s struck by a cue stick applying

Question

A 0.17-kg cue ball rests on the pool table. It's struck by a cue stick applying force F1 = 18 N i + 27 N j.

A) Determine the magnitude of the ball's acceleration.

B) Determine the direction of the ball's acceleration.

C) If the force was applied for 0.015 s, what's the ball's final speed?

Part A A 0.17-kg cue ball rests on the pool table. It's struck by a cue stick applying force F1 -18 N i+27 N 3. Determine the magnitude of the ball's acceleration. Express your answer to two significant figures and include the appropriate units a= Value Units Submit Request Answer Part B Determine the direction of the ball's acceleration. Express your answer to two significant figures and include the appropriate units 0Value Units Submit Request Answer Part C f the force was applied for 0.015 s, what's the ball's final speed? Express your answer to two significant figures and include the appropriate units Value Units

Explanation / Answer

a)F1 = 18i + 27j

acceleration = F/ m = (18 i +27j) / 0.17

= 105.88i + 158.82 j

magnitude = sqrt ( 105.88^2 + 158.82^2) = 190.88 m/s2

b) direction = tan^-1(158.8 / 105.88) = 56.3o

c) momentum = F*t

mv = (18i + 27j)*0.015

0.17*v = (18i + 27j)*0.015

v = 1.58i + 2.38j

speed = sqrt(1.58^2 + 2,38^2) = 2.85 m/s

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