52. QC Jumper cables are con-_LL__ nected from a fresh battery in one car to cha
ID: 1585375 • Letter: 5
Question
52. QC Jumper cables are con-_LL__ nected from a fresh battery in one car to charge i+ 0.01 1.00 0.06 Starter battery 1 12V11 12V1 in another car. L Figure P21.52 Live shows the circuit battery|battery diagram for this situation. While the cables are connected, the ignition switch of the car with the dead battery is closed and is activated to start the engine. Determine the -- Dead. Ignition switch Figure P21.52 nt (a) the starter and (b) the dead battery. () is the dea tery being charged while the starter is operatingExplanation / Answer
1 ohm and 0.06 ohm are in parallel and their combination is given as
Req = 1 x 0.06/(1 + 0.06) = 0.057 ohm
total resistance is given as
Rtotal = Req + r = 0.057 + 0.01 = 0.067 ohm
i = current coming from the live battery = Elive/Rtotal = 12/0.067 = 179.1 A
V = Voltage across the dead battery and starter = i Req = 179.1 x 0.057 = 10.2 Volts
istarter = current in starter = V/0.06 = 10.2/0.06 = 170 A
b)
idead = current in dead battery = V/1 = 10.2/1 = 10.2 A
c)
yes the dead battery is being charged.
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