let D1=1.00cm and d2=5.00 cm Need Help? Read it 0/10 points | Previous Answers S
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let D1=1.00cm and d2=5.00 cm
Need Help? Read it 0/10 points | Previous Answers SerCP11 16.P017 The three charges in the figure below are at the vertices of an isosceles triangle. Let q 5.50 nC and calculate the electric potential at the midpoint of the base. (Let di 1.00 1.98 The response you submitted has the wrong sign. kv Need Help? IuReaan 10/10 points | Previous Answers SercP11 16.P030 (a) When a 3.50-V battery is connected to the plates of a capacitor, it stores a charg e of 26.0 c, what is the value of the capacitance?Explanation / Answer
Given,
d1 = 1 cm ; d2 = 5 cm ; q = 5.5 nC
We need to find the potential at the mid point of the base.
The potential at the mid point of the base will be the sum of potentials due to three charges
V = 2 V(-q) + V(+q)
V = 2 k q/r + k q/r'
distance of mis point from +q is:
r' = sqrt (d2^2 - d1/2^2) = sqrt (5^2 - 0.5^2) = 4.97 cm = 0.0497 m
V = 9 x 10^9 x 10^-9 (-2 x 5.5/0.005 + 5.5/0.0497) = -18804 V
Hence, V = -18804 V
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