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The lug nuts on your cars tires have been tightened with a torque of 40.0 N m. T

ID: 1585746 • Letter: T

Question

The lug nuts on your cars tires have been tightened with a torque of 40.0 N m. The tire iron that came with the car is only 20.0 cm long, but you are able to place it exactly perpendicular. How much force do you have to exert in order to break the lug nuts free The lug nuts on your cars tires have been tightened with a torque of 40.0 N m. The tire iron that came with the car is only 20.0 cm long, but you are able to place it exactly perpendicular. How much force do you have to exert in order to break the lug nuts free

Explanation / Answer

torque = T = 40 N-m

length = l = 20 cm = 0.2 m

angle = theta = 90

torque T = r F sin ( theta)

          40 = 0.2 * F * sin90

                        forec F = 200 N