2. [1pt] The figure below shows two points in an E-field: Point 1 is at (X1,Y1)

Question

2. [1pt] The figure below shows two points in an E-field: Point 1 is at (X1,Y1) = (3,4) in m, and Point 2 is at (X2,Y2) = (12,9) in m. The Electric Field is constant, with a magnitude of 62 V/m, and is directed parallel to the +X-axis. The potential at point 2 is 442 V. Calculate the potential at point 1.

Hint: The lines in the figure are the electric field lines. Draw equipotential lines and caculate the difference in potential. (This involved the E-field which is given, and the (relevant!) distance... which distance matters?). How is the potential at point 1 related to the potential at point 2, if you know the change (difference) in potential between them? Think very carefully about signs, which point should be at the higher potential, 1 or 2!

Explanation / Answer

(a).

V = E r

V at point 2 is

V2 = V1 - E r

442 = V1 - 62(12 - 3)

V1 = 442+558 Volts

V1=1000 V

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