In the quark model of fundamental particles, a proton is composed of three quark

Question

In the quark model of fundamental particles, a proton is composed of three quarks: two "up" quarks, each having charge +2e/3, and one "down" quark, having charge -e/3. Suppose that the three quarks are equidistant from one another. Take the distance to be 1.30×10-15 m and calculate the potential energy of the subsystem of two "up" quarks. (MeV)

potential energy of 2 "up" quarks calculated to be 4.92×10-1 MeV (this is correct)

I just need help with the part below:

Calculate the total electric potential energy of the three-particle system. (MeV)

Explanation / Answer

Charge of Up quark, q = +2e/3
Charge of Down quark, q = -e/3

Distance between quarks, r = 1.30 * 10^-15 m

Total electric potential energy of the three-particle system, = k*q1q2/r + k * q2q3/r + k*q1q3/r

U = k/r * [q1q2 + q2q3 + q1q3]
U = (8.9*10^9)/(1.30 * 10^-15 ) * 1.6*10^-19* [2/3 * 2/3 - 2/3*1/3 - 2/3 * 1/3]
U = (8.9*10^9)/(1.30 * 10^-15 ) * 1.6*10^-19 * 0
U = 0
Total electric potential energy of the three-particle system, U = 0

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