1. The motion of a singly ionized negatively charged ion moving parallel to the

Question

1. The motion of a singly ionized negatively charged ion moving parallel to the x axis is tracked. At x=5 cm the particle has 1.28 x 10-16 J of kinetic energy at x=8 cm the kinetic energy is 1.0 x 10-16 J at x=11 cm, 8.8 x 10 -17 J and at x=14 cm, 8.4 x 10-17 J. a) Is there an electric field present? If so, in which direction does the fields x component point? Explain your reasoning. b) Is the field uniform? How can you tell? c) Field present or not, at each of the four positions the electric potential can be measured. Devise two sets (four measurements each) of electrical potential values that are consistent with the data given.

Explanation / Answer

a) here electric field is present but it is action opposite to the electrons direction because kinetic energy of the electron is decreasing

b) here field is uniform f = qE

ma = qE

acceleration is proportional to the electric field

c) kinetic energy = q* change in potential

1) potential = 1.28*10^-16/1.6*10^-19 = 800 volts

2) potential = 1*10^-16/1.6*10^-19 = 625 volts

3) potential = 8.8*10^-17/1.6*10^-19 = 550 volts

4) potential = 8.4*10^-17/1.6*10^-19 = 525 VOLTS

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