The magnetic field of an electromagnetic wave in a vacuum is B z =(2.0 T)sin((1.

Question

The magnetic field of an electromagnetic wave in a vacuum is Bz=(2.0T)sin((1.1×107)x2ft), where x is in m and t is in s.

Part A

What is the wave's wavelength?

Express your answer with the appropriate units.

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Part B

What is the wave's frequency?

Express your answer with the appropriate units.

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Part C

What is the wave's electric field amplitude?

Express your answer with the appropriate units.

The magnetic field of an electromagnetic wave in a vacuum is Bz=(2.0T)sin((1.1×107)x2ft), where x is in m and t is in s.

Part A

What is the wave's wavelength?

Express your answer with the appropriate units.

=

SubmitMy AnswersGive Up

Part B

What is the wave's frequency?

Express your answer with the appropriate units.

f =

SubmitMy AnswersGive Up

Part C

What is the wave's electric field amplitude?

Express your answer with the appropriate units.

E =

Explanation / Answer

comparing wit the general equation

B = Bmax*sin(kx-wt)

Bmax = 2 uT

wave number k = 1.1*10^7

angular frequency is w = 2*pi*f

A) wave's wavelength is lamda = (2*pi)/k = (2*3.142)/(1.1*10^7) =5.71*10^-7 m =571 nm

B) wave's frequency is f = w/(2*pi)

here w is the angular frequency

C) electric field amplitude is E = c*Bmax = (3*10^8*2*10^-6) = 600 N/C

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