Save All Answers Save and Submit stion 1 2 points Saved In each of the drawings

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Save All Answers Save and Submit stion 1 2 points Saved In each of the drawings below a small electric charge is being moved within an electric field. In each d the same, and the distance d that the charge is being moved is the same. Rank the three drawings in charge is being moved is the same. Rank the three drawings in order from the most work done by E on E (the electric field) is the same, the charge that is being moved is order from the most work done by E on the charge to the least work done by E on the charge. 4 D Most work done on the charge by the electric field E 2 Intermediate amount of work done by the electric fieid E on the charge . Least work done on the charge by the electric field E 1. Not enough information to determine the answer 2. Drawing c Drawing a 4. Drawing b 2 points Save Answer Question 2 n each ofthe drawings below a small electric charge is being moved within an electric field. In each di E (the electric field) is the same, the that is being moved is the same, and the distance d that the charge is being moved is the same. Rank the three drawings in order from the larges potential difference between A and B t potential difference between A and s to the lowest 1. Drawing b 2. Drawing c 3. Drawing a 4. Not enough information to determine the answer Largest potential difference between A and B G Intermediate potential difference between A and B Smalless potential difference between A and B 2 points Save Anwer Question 3 E (the electric field) is the same, the charge that is being moved is l the in each of the deawings below a small electric charge is being moved within an electric field. in each ne on es-en- the same are the distanced that the charge is e ng moved is th, same, Rank the ther energy between points B and a on n order h n i e e·m e

Explanation / Answer

1). increasing order: b,c,a

2).  increasing order: a,c,b

3). increasing order: a,c,b

4). Work done = Fd =EQd = 3x10-8 J

5). PE difference = Workdone = 3x10-8 J

6). Potential difference = PE/Q = 6V

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