Magnetic Field Due to a Straight Current Carrying Wire For a long straight wire

Question

Magnetic Field Due to a Straight Current Carrying Wire For a long straight wire carrying a current I, the magnitude of the magnetic field, B produced at a perpendicular distance, r from a wire is given by where mew_0 = 4pi10^-7 N/A^2 or is the magnetic permeability of free space and is a constant. The amount of electric current, I is measured in Amperes (A) and r is measured in m. Thus the circle formed by the distance r from the wire has magnetic field of the same magnitude. However, the direction of the magnetic field at a point on the circle is the tangent at that point. Since there are two possible directions for the tangent, the direction, by convention, is determined by the right hand rule. Learn more using java applet simulations. Study the applet carefully and answer the following questions. The figure above shows a wire perpendicular to the page. The wire carries a current I = 2.1 A flowing into the page. Your first task is to find the direction of the magnetic field at various points at a distance r = 0.25 m from the wire. Use the compass rose for the direction. The direction of the magnetic field at D is along The direction of the magnetic field at A is along The direction of the magnetic field at E is along The direction of the magnetic field at C is along The next step is to calculate the strength of the magnetic field at the various points. Since they are all the same distance from the current, the magnitude of the magnetic field is the same for all the points. What is the magnetic field at G? The unit for magnetic field is T (Tesla).

Explanation / Answer

Directions are as follow -
NW
SW
NE
E

B = (uo* I)/(2*pi*r)
B = (4*PI*10^-7 * 2.1)/(2*PI*0.25)
B = 1.68 * 10^-6 T
Strength of Magnetic Field, B = 1.68 * 10^-6 T

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