Suppose you are going to measure Young\'s modulus for three rods by measuring th

Question

Suppose you are going to measure Young's modulus for three rods by measuring their stretch when they are suspended vertically and weights are hung from them, as shown. three hanging rods Rod 1 is 3 meters long and cylindrical with radius 7 mm (1 millimeter is 0.001 m). Rod 2 is 3.3 meters long by 14 mm wide by 7 mm deep. Rod 3 is 1.5 meters long by 8 mm wide by 8 mm deep. The definition of Young's modulus, Y = (F/A)/(capital deltaL/L), includes the quantity A, the cross-sectional area. (a) What is the cross-sectional area of rod 1? A = m2 (b)) What is the cross-sectional area of rod 2? A = m2 (c)) What is the cross-sectional area of rod 3? A = m2 - please make answers clear as what section they belong to. thank you :)

Suppose you are going to measure Young's modulus for three rods by measuring their stretch when they are suspended vertically and weights are hung from them, as shown. 2 Rod 1 is 3 meters long and cylindrical with radius 7 mm (1 millimeter is 0.001 m). Rod 2 is 3.3 meters long by 14 mm wide by 7 mm deep. Rod 3 is 1.5 meters long by 8 mm wide by 8 mm deep. The definition of Young's modulus, Y = (F/A)/(M/L includes the quantity A, the cross-sectional area. (a) What is the cross-sectional area of rod 1? A= (b)) What is the cross-sectional area of rod 2? A= (c)) What is the cross-sectional area of rod 3? m2 m2 m2

Explanation / Answer

a) cross sectional area of rod 1 =*r^2

=3.14*(6*10^-3)^2

=1.13*10^-4 m^2

b)  cross sectional area of rod 2 = width * depth

=15*10^-3 * 3*10^-3

=45*10^-6 m^2

c) cross sectional area of rod 3 =width*depth

=5*10^-3 * 5*10^-3

=25*10^-6 m^2

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