The 2.3-cm-diameter solenoid in (Figure 1) passes through the center of a 6.0-cm

Question

The 2.3-cm-diameter solenoid in (Figure 1) passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.50 T .

Part A

What is the magnetic flux through the loop when it is perpendicular to the solenoid?

Express your answer using two significant figures.

2.1×104

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Correct

Part B

What is the magnetic flux through the loop when it is tilted at a 60 angle?

Express your answer using two significant figures.

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Figure 1 of 1

The 2.3-cm-diameter solenoid in (Figure 1) passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.50 T .

Part A

What is the magnetic flux through the loop when it is perpendicular to the solenoid?

Express your answer using two significant figures.

=

2.1×104

  Wb (Correct)

SubmitMy AnswersGive Up

Correct

Part B

What is the magnetic flux through the loop when it is tilted at a 60 angle?

Express your answer using two significant figures.

=   Wb  

SubmitMy AnswersGive Up

Incorrect; Try Again; 1 attempt remaining

(Please help me. One attempt remains)

Figure 1 of 1

Explanation / Answer

The diameter of the solenoid d = 2.3cm



then the radius of the solenoid r = 2.3/2 =1.15 cmcm



the magnetic filed B = 0.50T



(a) flux=(magnetic field)(area)(costheta) The magnetic flux through the loop:


= BAcos



= Br^2 cos90



= (0.50T)(1.15*10^-2m)^2



= 0.01806415 Tm^2 or Wb






(b) when it is tilted at = 60

There is no change in flux when it tilts so the answer is the same: 0.01806415 Tm^2 or Wb

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