billiard ball with inertia mb = 0.25 kg and a ball made out of Silly Putty with

Question

billiard ball with inertia mb = 0.25 kg and a ball made out of Silly Putty with inertia mp = 0.25 kg collide and stick together. If their initial velocities were +1m/s and 2m/s respectively, (a)[4 pts] What is the momentum of the system before the collision? (b)[3 pts] What is the momentum of the system during the collision? (c)[5 pts] What are their final velocities? (d)[3 pts] What is the momentum of the system after the collision? (e)[3 pts] What is the change in momentum of mb? (f)[3 pts] What is the change in momentum of mp? (g)[3 pts] What is the change in momentum of the system?

Explanation / Answer

a)  The momentum of the system before the collision= mb*vb + mp*vp

= 0.25*1 - 0.25*2 = -0.25 kgm/s

b) The momentum of the system during the collision = -0.25 kgm/s

c) Final Velocity = V =(mb*vb + mp*vp)/(mb + mp) =-0.25/0.50 = -0.5 m/s

d) The momentum of the system after the collision = (mb + mp)*V =0.5*(-0.5) = -0.25 kgm/s

e)       The change in momentum of mb = mb*V - mb*vb = mb(V - vb)

= 0.25 (-0.5 - 1) = -0.375 kgm/s

f)    The change in momentum of mp = mp*V - mp*vp = mp(V - vp)

= 0.25 (-0.5 + 2) = 0.375 kgm/s

g)    The change in momentum of the system = 0

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