Will you please elaborate on the coefficient of kinetic friction, as in how to d

Question

Will you please elaborate on the coefficient of kinetic friction, as in how to derive this particular one, or a general derivation of a kinetic friction coefficient accessible to a first year student, and its meaning, please and thanks!

04.2A block with mass m -8.0 kg sits on an inclined plane. The angle of the plane with the horizontal is = 25°. (The figure is not drawn to scale). A force F is applied to the block at an angle = 30°, as shown. The minimum force required to keep the block from slipping down the incline is 20 N. The coefficient of kinetic friction is = 0.20 . (a) Draw the free- body diagram of the block. (b) What force F is required to push the block up the incline at constant speed? What is the normal force? [Assume g = 9.8 m/s.]

Explanation / Answer

force equation of the block

to keep the block in constant speed that means acceleration will be 0

mg * cos(theta) - k * (mg * sin(theta) + F * sin(phi)) - F * cos(phi) = 0

8 * 9.8 * cos(25) - 0.2 * (8 * 9.8 * sin(25) + F * sin(30)) - F * cos(30) = 0

F = 66.69 N

normal force = (8 * 9.8 * sin(25) + F * sin(30))

normal force = (8 * 9.8 * sin(25) + 66.69 * sin(30))

normal force = 66.47 N

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