A satellite in outer space is moving at a constant velocity of 21.0 m/s in the +

Question

A satellite in outer space is moving at a constant velocity of 21.0 m/s in the +y direction when one of its onboard thruster turns on, causing an acceleration of 0.320 m/s2 in the +x direction. The acceleration lasts for 42.0 s, at which point the thruster turns off. (a) What is the magnitude of the satellite's velocity when the thruster turns off? m/s (b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis. ° counterclockwise from the +x-axis

Please give a step by step response

Explanation / Answer

Here ,

initial velocity , u = 21 j m/s

acceleration, a = 0.32 i m/s^2

time , t = 42 s

a) let the final velocity is vf

vf = u + a * t

vf = 21 j + 0.32 * 42 i

vf = 13.44 i + 21 j

vf= sqrt(13.44^2 + 21^2) at arctan(21/13.44) degree

vf = 24.93 m/s at 57.4 degree

the magnitude of satellite's velocity is 24.93 m/s

b)

the direction of satellite's velocity is 57.4 degree

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