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1)Metal spheres A and B initially neutral in contact. Positive C sphere brought

ID: 1590478 • Letter: 1

Question

1)Metal spheres A and B initially neutral in contact. Positive C sphere brought near A, not touching. A)Is A positive, neutral, or negative? Explain? A is negative due to polarization on A and B the positive charge is pushed to B and the negative charge is attracted to A. B)Sphere C having charge Q, touched sphere A originally. C is removed and A and B seperated. Describe charge states. Explain? When C touches A, A and B acted as one by conduction, doubles the size of C so A and B will be charged 2/3 Q and C 1/3 Q after touching A. A an B are seperated, they are equal in size so they each will have a charge of 1/3 Q C)Distance between A and B after seperation is 8cm, electrostatic force between them is 0.05N. Determine Q?

Part C is what I don't understand. I think maybe I should use Coulombs law but not sure.

Explanation / Answer

(C)
Charge on A, qa = Charge on B, qb = 1/3 * Q

Distance, r = 8.0 cm = 0.08 m
Force , F = 0.05 N

Force is given by the Formula,
F = K*qa*qb/r^2
0.05 = (8.9 * 10^9 * Q/3* Q/3)/0.08^2
Q = 5.68 * 10^-7 C