C 29%, D ooo Verizon 1:22 AM session masteringphysics.com C Phy 201 Spring 2016

Question

C 29%, D ooo Verizon 1:22 AM session masteringphysics.com C Phy 201 Spring 2016 Night Problem 4.43 A small box is held in place against a rough vertical wall by someone pushing on itwith a force directed upward at 35 above the horizontal. The coefficients of static and kinetic friction between the box and wall are 0.40 and 0.30, respectively. The box slides down unless the applied force has magnitude 29 N What is the mass of the box? ress your answer to two significant figures and include the appropriate units. Value Units Submit My Answers Give up

Explanation / Answer

Given

theta = 35 degrees

mue_s = 0.4

mue_s = 0.3

F = 29 N

let m is the mass of the box.

when 29 N is applied the box will be in equilibrium.

so, net force is zero.

Let N is the normal force exerted by the wall on box.

Apply, Fnetx = 0

F*cos(35) - N = 0

N = F*cos(35)

= 29*cos(35)

= 23.76 N

now Apply, Fnety = 0

F*sin(35) + N*mue_s - m*g = 0

==> m = (F*sin(35) + N*mue_s)/g

= (29*sin(35) + 23.76*0.4)/9.8

= 2.67 kg <<<<<<<<<<<<--------------Answer

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