Jump to Hrs 202 . Spring! 6 . KALK Activities and Due Dates due 2/19 2/11/2016 0
ID: 1591998 • Letter: J
Question
Jump to Hrs 202 . Spring! 6 . KALK Activities and Due Dates due 2/19 2/11/2016 08:00 AM21.1/100 Gradebook m Print il Calcular Period. Table Question 9 of 14 Mapm A paper-filled capacitor is charged to a potential difference of 2.4 V and then disconnected from the circuit. The dielectric constant of the paper is 3.7. Keeping the plates insulated, the paper filling is allowing air to fill the capacitor instead. Find the resulting potential difference of the capacitor Number While continuing to keep the capacitor's plates insulated, an unknown substance is inserted between them. The plates then attain a potential difference that is 0.61 times the original potential difference (when paper illed the capacitor). What is this substance's dielectric constant? O previous oeck Answer Next Ex.Explanation / Answer
Here ,
voltage , V = 2.4 V
dielectric constant , k = 3.7
let the final potential difference is V1
as the charge on the capacitor will be same
C1 = C/k = C/3.7
C1 * V1 = C * V
C/3.7 * V1 = C * 2.4
V1 = 8.88 V
the resulting potetnial difference is 8.88 V
let the dielectric is k
as V2 = 0.61 * V
as charge is constant
C2 * V2 = C * V
k * C * 0.61 * V = C * V
k = 1/.61
k = 1.64
the dielectric constant is 1.64
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.