when a charge of 30.0 c moves from (0,0) to (0,2). (h) what if it goes from (0,0
ID: 1592073 • Letter: W
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when a charge of 30.0 c moves from (0,0) to (0,2). (h) what if it goes from (0,0) to (2,3)2 Ans (a) 2.25 x 10' N; V,-+ 8.99 x 106 volt. (f) U=-90J (g) ? (b) E =b-4.50 x 108 N/C; (c) 9.00 x 10° NC; (d),V--899 x 10° volt; Net V = 0 (e) V,--6.36 x i0° volt; ; V,-+6.36 x 10 volt, Net-o volt; (h) 71 .9 J 05) If the plates of the capacitor in prob. 03) are separated by d-2.00 mm, calculate: (a) the potential difference between the plates; (b) the capac plates; (b) the capacitance). Recall -8.85 x 10 Ants; (a) 30.3 kilovolt; (b) 99.6 pF (= 10-12) (picoFarads) 069) Calculate the capacitance of the sphere of Prob. 02) and its energy U Ans 148 picoFarads, 0,0239 J. 07) Find the equivalent capacitance of FIVE capacitors each having 15.0 uF and connected: (a) all in series; (b) all in parallel. (Make drawings). Ans (a) 3.00F ; (b) 75.0 F 06) Calculate the ca 08) If the previous capacitor networks are connected to a potential difference of 15.0 volt at their ends, find (a)the charge in each capacitor and (b) the potential difference across each. es Qi-45pC and AV 3.00 v, in, parallel Vpl 5.0 v and Q-225 pC 09) What is the total energy "stored" in the previous capacitive networks? 84.38 euExplanation / Answer
Here,
8)
potential difference , Vd = 15 V
a) in series ,
Ceq = 3 uF
charge on capacitor = Vd * Ceq
charge on capacitor = 15 V * 3 uF
charge on capacitor = 45 uC
the charge on capacitor in series is 45 uC
for potential at each capacitor ,
V = Q/C
V = 45 uC/(15 uF)
V =3 V
the potential across the capacitor in series is 3 V
b) in parallel connection
Ceq = 75 uF
charge on each capacitor = C * V
charge on each capacitor = 15 uF * 15 V
charge on each capacitor = 225 uC
in parallel ,voltage across each capacitor = potential applied
voltage across each capacitor = 15 V
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