Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Homework 4 Projectile M... x c hysics question l Chegg.c... x M Danion Meredith

ID: 1592670 • Letter: H

Question

Homework 4 Projectile M... x c hysics question l Chegg.c... x M Danion Meredith has news x s Danjon Meredith I StyleSeat X 3 b/Student/Assig dep 13131533 Search Need Help? Talk to a Tutor VA Homework 4-Projectile M... x c hysics question Chegg x 3 b/Student/Assig dep-13131533 Search Need Help? Read it Talk to a Tutor 3.95/6 points Previous Answers SerPSE8 4.P007.M My Notes C+ Ask Your Teacher A fish swimming in a horizontal plane has velocity vi 4.00 i 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is ri 16.0 i 2.60 j) m. After the fish swims with constant acceleration for 19.0 s, its velocity is v 3 15.0 i 1.00 j) m/s. (a) What are the components of the acceleration of the fish? ax 0.579 m/s ay B 0.1053 m/S (b) What is the direction of its acceleration with respect to unit vector i? -0.179 at the origin. rite the numerical values for the X and y components and Draw coordinate axes on a separate piece of paper, and then add the acceleration vector with its ta then use this drawing to determine the angle counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t 24.0 s? x 281.75 Y 8.926 In what direction is it moving?

Explanation / Answer

here,

initial velocity , u = ( 4i + j) m/s

final velocity , v = ( 15 i - 1 j)

initial position ,r = (16 i - 2.6 j) m

time taken , t = 19 s

(a)

let the accelration be a

a = ((vx - ux)/t) i + ((vy- uy)/t) j

a = ((11/19) i + (-2/19) j) m/s^2

a = 0.5789 i m/s^2 - - 0.105 j m/s^2

(b)

theta = arctan( - 0.1053 /0.5789)

theta = 349.69 degree counterclockwise from the + x axis