A block is at rest on the incline shown in the figure. The coefficients of stati

Question

A block is at rest on the incline shown in the figure. The coefficients of static and kinetic friction are µs = 0.67 and µk = 0.57, respectively. The acceleration of gravity is 9.8 m/s 2. and the angle is 30.

Part A: What is the frictional force acting on the 38 kg mass?

Part B: What is the largest angle which the incline can have so that the mass does not slide down the incline? Answer in units of degress.

Part C: What is the acceleration of the block down the incline if the angle of the incline is 37 ? Answer in units of m/s 2 .

Explanation / Answer

Given that

The coefficients of static and kinetic friction are µs = 0.67 and µk = 0.57

The acceleration of gravity is (g) =9.8 m/s 2

Mass of the object is m =38kg

Now we know that the

Frictional force is

fs =us*Ncostheta

The normal force is given by N =mgcsotheta =38*9.81cos(30) =322.836N

Now the frictional force is given by

fs =us*N =0.67*322.836 =216.30N

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