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You are pushing a 4.75-kg box toward the right as it moves, in the direction of

ID: 1592817 • Letter: Y

Question

You are pushing a 4.75-kg box toward the right as it moves, in the direction of your push, over a patch of rough grass. Construct the free-body diagram for the box by corectly arranging the arrows in the diagram. Each force acting on the box should be indicated by an arrow starting at the dot in the center of the box. The arrows are labeled according to the following key:

W=weight of the box, F=Force of your push, g=acceleration due to gravity, N=normal force from ground, and f=friction force from grass

If the magnitude of you push is 34.2 N, and the coefficient of kinetic friction with the grass is 0.350, what will be the magnitude and direction of the accerleration of the box?

Explanation / Answer

F to the right, f to the left, W down and N up.
"g" is not a force and does not go on the diagram.

Net horizontal force Fnet = F - µmg = 34.2 N - 0.350*4.75kg*9.8m/s²
Fnet = 17.90 N
Then a = Fnet / m = 17.90N / 4.75 kg = 3.76m/s²

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