9. For the same situation as in Question 8, what is the force of static friction

Question

9.

For the same situation as in Question 8, what is the force of static friction of the SUV on the road?

10.

In questions 8 and 9, what is the minimum value of the coefficient of static friction there can be between the SUV's tires and the road in order to have this acceleration?

An SUV, with a mass of 750 kg, is accelerating forward on a level road at 4 m/. What is the magnitude and direction of the force of static friction of the road on the SUV? (Assume there are no drag forces, and the tires are rolling).

A) 300 Newtons towards the back of the SUV
B) 3000 Newtons towards the front of the SUV
C) 187.5 Newtons towards the front of the SUV
D) none, since the SUV is moving, the force of friction is kinetic, not static.
E) 187.5 Newtons towards the back of the SUV

9.

For the same situation as in Question 8, what is the force of static friction of the SUV on the road?

A) 3000 Newtons towards the front of the SUV
B) 187.5 Newtons towards the back of the SUV
C) zero, since the SUV is moving, the friction is kinetic, not static.
D) 3000 Newtons towards the back of the SUV
E) 187.5 Newtons towards the front of the SUV

10.

In questions 8 and 9, what is the minimum value of the coefficient of static friction there can be between the SUV's tires and the road in order to have this acceleration?

A) 0.408
B) 4
C) 306
D) 1.000
E) 2.45

Explanation / Answer

8 .

using Newton's 2nd law ,

Fnet = m a

F = 750 x 4 = 3000 N towards the front of the SUV

10 .

friction = u N = 3000

u mg = 3000

u x 750 x 9.81 = 3000

u = 0.408

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