A system of saturated water at 200 °C has a specific volume of 0.08 m^3/kg. Find

Question

A system of saturated water at 200 °C has a specific volume of 0.08 m^3/kg. Find the saturation pressure (bar) of the system and calculate the vapor quality (x) of the system. A system of saturated water at 200 °C has a specific volume of 0.08 m^3/kg. Find the saturation pressure (bar) of the system and calculate the vapor quality (x) of the system. A system of saturated water at 200 °C has a specific volume of 0.08 m^3/kg. Find the saturation pressure (bar) of the system and calculate the vapor quality (x) of the system.

Explanation / Answer

From steam table : At 200 0C

Result:

Steam Pressure14.5335 bar abskg/cm² absmm

Specific Volume of Saturated Steam= 0.127222 m³/kg

Specific Volume of Saturated Water =   0.00115651 m³/kg.

Given specific volume = .08 m³/kg = Vl + x* Vg  = (0.127222 *x + 0.00115651) m³/kg

On solving , we get x = 0.6197 ( approx. = .62)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.