At the instant the displacement of a 2.00 kg object relative to the origin is d

Question

At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) i + (4.00 m) j - (3.00 m) k , its velocity is v = - (7,42 m/s) i +(8.24 m/s) j + (1.57 m/s) k and it is subject to a force & = (1.53 N) i -(5.63N) j + (8.49 N) k . Find the acceleration of the object ((a), (b) and (c) for i, j and k components respectively), the angular momentum of the object about the origin ((d), (e) and (f) for i , j and k components respectively), the torque about the origin acting on the object ((g), (h) and (i) for i , j and k components respectively), and (j) the angle between the velocity of the object and the force acting on object. Number units. Number units

Explanation / Answer

a) acceleration for i component = 0.765 i   m/sec2

b) acceleration for j component = -2.815 j m/sec2

c) acceleration for k component = 4.245 k m/sec2

d) angular momentum for i component = 62 kg*m2/s

e)   angular momentum for j component = 38.24 kg*m2/s

f)    angular momentum for k component = 92.32 kg*m2/s

g) torque about origin for i component = -17.07 N-m

h)   torque about origin for j component = 21.57 N-m

i)   torque about origin for k component = 17.38 N-m

j)   angle between velocity and Force = 112.64 degrees

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