Please help me answer the questions. The data I collected was done by these equa
ID: 1593897 • Letter: P
Question
Please help me answer the questions. The data I collected was done by these equations: a=(v^2-vi^2)/2(d) Stopping acceleration=-14.63
Vf^2=0m/s^2+2(9.8m/s^2)(.1meters) Final velocity or velocity on impact= 1.4m/s
time it took for the knife to hit the penut butter= (0-1.4m/s)/9.8m/s^2=.14 seconds
Time it took for the knife to stop when enetering the penut butter. 1.4/-14.63m/s^2=-.1 seconds
Table 4.1a: Free fall (in air) Supply units for all quantities not in data tables] Drop displacement: - Drop displacement: xdop-lou-.in stan chelm q % m/S Standard free fall acceleration: a-= Initial velocity: v.- Calculated impact velocity: v.- 1 :4 M/s [Supply units for all quantities not in data tables] 5 AVG l.um/5 Onk Calculated impact velocity: v,= Final velocity: v.- Final velocity: v,= Seconds Calculated stopping acceleration: uCalculated stopping timeSecend Calculatedstoppingacceleration: as,--HL,Calculatedstoppingtime: to,- Supply units for all quantities not in data tables]Explanation / Answer
To get the impact velocity we use Vi^2=U^2-2*g*h =0+2*(-9.8)*0.1=1.96
So, Vi=1.4m/s
Here final velocity is 0 because particle come to rest.
To calculate stopping acceleration we use a=(U^2-Vi^2)/2*s =(0-1.4^2)/2*6.7=-14.63m/s^2
Time required= 1.4/(-14.63)= 0.1s
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