On level ground a shell is fired with an initial velocity of 46.0 m/s at 70.0 ab

Question

On level ground a shell is fired with an initial velocity of 46.0 m/s at 70.0 above the horizontal and feels no appreciable air resistance.

Part A

Find the horizontal and vertical components of the shell's initial velocity.

Enter your answers numerically separated by a comma.

v0h , v0v=                  m/s

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Part B

How long does it take the shell to reach its highest point?

Express your answer using three significant figures.

t=         

Part C

Find its maximum height above the ground.

Express your answer using three significant figures.

h(max)=

Part D

How far from its firing point does the shell land?

Express your answer using three significant figures.

L=

Part E

At its highest point, find the horizontal and vertical components of its acceleration.

Enter your answers numerically separated by a comma.

ah , av=                               m/s^2

Part F

At its highest point, find the horizontal and vertical components of its velocity.

Enter your answers numerically separated by a comma.

vh , vv=                                 m/s

Explanation / Answer

a) Horizontal component = (cos 70) x 46 = 15.73 m/sec.
Vertical component = (sin 70) x 46 = 43.23 m/sec.

b) Time to max. height = (v/g), = 43.23/9.8, = 4.41 secs. (Use vertical component only).

c) Height attained = (v^2/2g), = 95.35 metres.

d) It will be in the air (2 x 4.41s) = 8.82 secs. Horizontal velocity component is 15.73 m/sec., so range = (15.73 x 8.82) = 138.74 metres.

e) At highest point, horizontal and vertical components of acceleration = 0.

f) At highest point, horizontal velocity component = 15.73 m/sec., and vertical component = 0.

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