Problem 26.71 Problem 26.71 A1 sa jaF capacitor that is initially uncharged conn

Question

Problem 26.71 Problem 26.71 A1 sa jaF capacitor that is initially uncharged connected in series with a 675 kin nesistor and an emf source with 53.7 V and negligible intermal resistanoe. The circuit is completed at t a 0, previous 17 of 8 Part A Just after the circuitiscompleted, what is the rate at which electrical energy is being dissipated in the resistor? Express your answer with the appropriate units. P. Value Units My Answers GheUp Part B A what value is the rate at which electrical energy is being dissipated in the resistor equal to the rate at which electrica energy is being oft stored in the capacitor? Express your answer with the appropriate units. t. Value Units Submit My Chr up Part C At the calculated in part B. what is rate at which electrica energy is being dissipatedin the esiston

Explanation / Answer

step;1

Given that

capacitance C=1.58*10^-6 F

resistance R=6.75*10^3 ohms

voltage v=53.7 v

step;2

now we find the rate of electrical energy stored in resistance

the rate of electric energy P=v^2/R=53.7^2/6.75*10^3=427.2*10^-3 w

step;3

now we find the time the rate of electrical energy stored is equal to the rate the electric energy stored in capacitor

P=u/t

P=(1/2*cv^2)/t

472.2*10^-3=(1/2*1.58*10^-6*53.7^2)/t

472.2*10^-3=2.28*10^-3/t

time t=4.83 ms

step;4

now we find the rate of electrical energy stored in resistance

P=i^2*R=(Q/t)^2*R=(VC/t)^2*R=(53.7*1.58*10^-6/4.83*10^-3)^2*6.75*10^3=2.1W

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