Consider a parallel-plate capacitor originally with a charge q_0, capacitance C_

Question

Consider a parallel-plate capacitor originally with a charge q_0, capacitance C_0, and potential difference Delta V_0. There is an electrostatic force of magnitude F_0 between the plates, and the capacitor has a stored energy U_0. The terminals of the capacitor are not connected to anything. (a) A dielectric slab with K_e > 1 is inserted between the plates. Which quantities increase? (Choose all that apply.) (A) q (B) C (C) Delta V (D) F (E) U (b) What is the direction of the electrostatic force on the dielectric slab while it is being inserted? (A) The force pulls the slab into the capacitor. (B) The force pushes the slab out of the capacitor. (C) There is no electrostatic force on the slab. (c) Later the dielectric slab is removed. What is the direction of the electrostatic force on the dielectric slab while it is being removed? (A) The force pulls the slab into the capacitor. (B) The force pushes the slab out of the capacitor. (C) There is no electrostatic force on the slab.

Explanation / Answer

Ans a) capacitance,q and u increases

b) The force pushes the slab out of the capacitor

c) The force pulls the slab into the capacitor

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