Can anyone please help me with this question showing steps? A circular coil cons
ID: 1598436 • Letter: C
Question
Can anyone please help me with this question showing steps?
A circular coil consisting of a single loop of wire has a radius of 9.74 cm and carries a current of 9.68 A. It is placed in a uniform external magnetic field, so that the normal to the loop makes an angle of theta = 56.0 degree with the direction of the field. If the coil feels a torque of 1.35 times 10^-2 Nm, what is the magnitude of the magnetic field? (in T) A 1.18 times 10^-2 B 1.48 times 10^-2 C 1.85 times 10^-2 D 2.31 times 10^-2 E 2.89 times 10^-2 F 3.61 times G 4.52 times 10^-2 H 5.64 times 10^-2Explanation / Answer
the torque on the coil is given by
C = B i a n cos(theta)
or, 1.35x10^-2 = B x 9.68 x 3.14 x (9.74x10^-2)^2 x 1 x cos(90-56)
or, B = 0.05644 Tesla = 5.644x10^-2 T..............ans option H)
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