A bullet (m=50 gram) is fired into an ice block (M =3 KG) resting on ice. The bu
ID: 1599135 • Letter: A
Question
A bullet (m=50 gram) is fired into an ice block (M =3 KG) resting on ice. The bullet is imbedded in ice block and they move together on ice. a. Find the common velocity they move together. b. Find the initial kinetic energy of the system. c. Find the final kinetic energy of the system. d. Find the percent energy loss. Two Bowling balls are moving toward each other and collide. Assume elastic collision. M= 2 kg moving at 3 m/sec, and m=1.8 kg moving at -4 m/sec. Find their velocities after the collision Find their total initial kinetic energy, and total final kinetic energy. Are they equal?Explanation / Answer
What is the velocity of the bullet?
Assuming it is 'v'
a)
Use the conservation of momentum:
mv+M*0 = (m+M)v'
where m is mass of bullet = 0.05 kg
M is mass of block at rest = 3 kg
v' = final velocity of the combined system
Solving for v', we get:
v' = 0.016v
b)
Initial KE = mv2/2 = 0.025 v2
c)
Final KE = (m+M)v'2/2 = 0.00039 v2
d)
Loss in KE = 0.0246 v2
% loss = (Loss/ Inital KE) *100 = 98.4%
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