15. A load of 94 kg is supported by a wire of length 1.74 m and cross-sectional

Question

15. A load of 94 kg is supported by a wire of length 1.74 m and cross-sectional area 0.0984 cm^2. The wire is stretched by 0.283 cm. The acceleration of gravity is 9.8 m/s^2 . Find the tensile stress. Answer in units of N/m^2.
16. What is the tensile strain?
17. Calculate Young’s modulus for the wire. Answer in units of N/m2.
Question 15, chap 9, sect 2. part 1 of 3 10 points A load of 94 kg is supported by a wire of length 1.74 m and cross-sectional area 0.0984 cm2. The wire is stretched by 0.283 cm. The acceleration of gravity is 9.8 m/s2 Find the tensile stress. Answer in units of N/m2. Question 16, chap 9, sect 2. part 2 of 3 10 points What is the tensile strain? Question 17, chap 9, sect 2. part 3 of 3 10 points Calculate Young's modulus for the wire. Answer in units of N/m2.

Explanation / Answer

Pa = N/m^2

L = 1.74 m

M = 94 kg

A = 0.0984 cm^2

g = 9.8 m/s^2

l = 0.283

Tensile stress = force/area

force = mass* gravity =mg

Stress = (94*9.8)/9.84*10^-6 = 9.36 * 10^7 Pa



Strain = Extension / Original length

Strain = 0.00283 /1.74

= 1.6264 * 10^-3


Young Modulus = stress/strain

Young Modulus = 5.75*10^10 Pa

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