While driving down the street, your friends car was hit by a truck from behind.

Question

While driving down the street, your friends car was hit by a truck from behind. The posted speed limit is 35 mph or 15 m/s. The mass of your friends car is 1600 kg while the truck is 1800 kg. Your friend is driving slower than 20 mph or 8.9 m/s on the road to prepare for a turn.

Assume that neither car tried to accelerate or decelerate after the collision. If the coefficient of kinetic friction is 0.7 for the car and truck with the road, how far do the car and truck slide until they stop after collision?

Explanation / Answer

from the informtion provided in the questions, I am trying to draw the inference that speed of truck was 15m/s

conserving momqntum,

15 ( 1800 ) + 8.9 (1600 ) = v ( 1800+ 1600)

v ( speed of combined mass) =(27000+ 14240)/ (3400) = 12.129 m/s

a(retardation) = 0.7 (g) = 6.86 m/s^2

v^2 =u^2 + 2as

0 = 12.129^2 + 2 ( 6.86) (s)

s= 10.722 m/s apprx

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