At the intersection of Texas Av and conversely believe a yellow, compact car wit
ID: 1599905 • Letter: A
Question
Explanation / Answer
Given
mc = 250 kg, mt = 1700 kg
car moving towards east and the truck moving towards north
so the momentum vectors of car and truck are
mc*u1c i+mc*u1c j = 250*u1ci + 0 j
for truck
mt*u1t i + mt*u1t j = 0 i +1700*u1t j
after the collision they stick together and moving with velocity 16 m/s in a direction of 34 degrees east of north so the angle with the horizontal is 56 degrees
now the final momentum vector is
(mc+mt)v cos theta i +(mc+mt) v sin theta j
(250+1700)16 cos56 i + (250+1700)16 sin56 j
17446.81859 i + 25865.97226 j
equating these with initial momentum
17446.81859 i + 25865.97226 j = 250*u1c i +1700*u1t j
u1c = 17446.81859/250 m/s = 69.78727436 m/s
u1t = 25865.97226 / 1700m/s = 15.2152778 m/s
the initial velocities of car and pick up trucks are
69.78727436 m/s,15.2152778 m/s.
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