4. 0.881 points I Previous Answers Tipler6 10.P041 My Notes Ask Your Teacher A 1

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4. 0.881 points I Previous Answers Tipler6 10.P041 My Notes Ask Your Teacher A 15-g coin that has a diameter equal to 1.4 cm is spinning at 13 rev/s about a fixed vertical axis. The coin is spinning on edge with its center directly above the point of contact with the tabletop. As you look down on the tabletop, the coin spins clock-wise. Its moment of inertia about an axis through its diameter is given in the figure below. Model the coin as a cylinder of length L and radius R and take the limit as L approaches zero. I- MR2+ MIA (a) What is the angular momentum of the coin about its center of mass? 1.5e-05 kg m2/s away from you (b) What is the coin's angular momentum (including direction) about a point on the tabletop 10 cm from the axis 1.5e-05 kg m /s away from you For the following questions, assume the coin spins about a vertical diameter at 13 rev/s while its center of mass travels in a straight line across the tabletop at 5.0 cm/s. (c) What is the angular momentum of the coin about a point on the line of motion of the center of mass? 1.5e-05 kg mes away from you (d) When it is both spinning and sliding, what is the angular momentum of the coin about a point 10 cm north of the line of motion of the center of mass? 9.0009e-05 X kg m2/s toward you You can find the total angular momentum of the coin from the sum of its spin and orbital angular momenta. eBook

Explanation / Answer

Solving last part of 11th question

Since angular momentum will be conserved

If r'=r/2,v'=2v

Initial energy=0.5*mv*v

Final energy=0.5*m*(2v*2v)

Work done=change in energy=(3/2)mv*v

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